Ontario Registered Pharmacy Technician (RphT) Practice Exam

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125mL of Cipro 5% suspension contains how many grams of active ingredient?

  1. 0.625g

  2. 6.25g

  3. 62.5g

  4. 60.25g

The correct answer is: 6.25g

This question asks about the amount of active ingredient in 125mL of Cipro 5% suspension. The active ingredient is represented by the percentage, so 5% means that 5% of the total volume is the active ingredient. To find the amount in grams, we need to calculate 5% of 125mL. 5% of 125mL is equal to 5/100 * 125 = 6.25g. This is the amount of active ingredient in 125mL of Cipro 5% suspension, which makes option B the correct answer. Option A, 0.625g, is incorrect because it represents 0.5% of 125mL which is not equal to 5%. Option C, 62.5g, is incorrect because it represents 50% of 125mL which